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added docstring to explain the ishighlighted method

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hugomanipoud2 2025-05-21 14:40:16 +02:00
parent f3be5c6f6c
commit 8dc6c67272
1 changed files with 22 additions and 9 deletions
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29
OOP_3B5_Project/src/backend/Board.java
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@ -239,15 +239,28 @@ public class Board {
}
} else if (type == PieceType.Bishop) {
int k = 8; // default range value for bishop to cover the board wherever he is
for(int i = 1; i < k;i++) {
if (getPiece(selectX + i, selectY + i) != null) {
k = i;
break;
}
if (selectX + i == x && selectY + i == y) {
isAPieceHere = true;
for(int i = 1; i < k; i++) { // range from 1 to k up until the follwing if statement is true
if (getPiece(selectX + i, selectY + i) != null) { // true Iff there is a piece at the specified position which are the direction of the specified piece !
if (color != getPiece(selectX + i, selectY + i).isWhite()) { // another condition that will be lauched IFF the case has a piece in it and IFF the piece is of a != color than the played piece
k = i+1; // if color is diffrent, change K to i (number of case before a piece) + 1 (if the piece is of a different color i can eat it)
if (selectX + i == x && selectY + i == y) { // iterates trough i but k = i+1 so the for loop will itterate until i+1 allowing for the opposite color piece to be eaten
isAPieceHere = true; //set the boolean var to true
}
break; // break the loop
} else {
k = i; // if the condition "if (color != getPiece(selectX + i, selectY + i).isWhite())" is not compliant, this else statement will change k to be i, hence, the same colored piece present in its path will not be eaten
break;
}
}
} k = 8;
if(selectX + i == x && selectY + i == y) { // iterate trough i up until i as k = i, it is needed to not light up the pieces of the same color a the played piece
isAPieceHere = true;//set the boolean var to true
}
} k = 8;
for (int i = 1; i < k; i++) {
if (getPiece(selectX - i, selectY - i) != null) {
k = i;